watt = joule/sec
time to use x joules is x / power so t = 108/23.54 = 4.59secHow long does it take for this battery to lose 108 J of chemical energy?Multiply 2.20 amps* 10.7 volts = 23.54 watts
108 Joules/23.5 watts = 4.59 seconds
Friday, September 23, 2011
How long does it take for this battery to lose 108 J of chemical energy?
A positive current of 2.20 A flows from the negative to the positive terminal inside a battery that has an emf of 10.7 V. How long does it take for this battery to lose 108 J of chemical energy?How long does it take for this battery to lose 108 J of chemical energy?power = volts x amps = 2.20A x 10.7 volts = 23.54 watts
watt = joule/sec
time to use x joules is x / power so t = 108/23.54 = 4.59secHow long does it take for this battery to lose 108 J of chemical energy?Multiply 2.20 amps* 10.7 volts = 23.54 watts
108 Joules/23.5 watts = 4.59 secondsimprove my well being first kiss advice
watt = joule/sec
time to use x joules is x / power so t = 108/23.54 = 4.59secHow long does it take for this battery to lose 108 J of chemical energy?Multiply 2.20 amps* 10.7 volts = 23.54 watts
108 Joules/23.5 watts = 4.59 seconds
