A. The potential difference applied between the plates is doubled?
B. The charge on each plate is doubled?
C. The separation between the plates is doubled, as the capacitor remains connected to the same battery?
D. The separation between the plates is halved, and the difference of the potential between the plates is doubled?How does the engery stored on a parallel plate capacitor change if:?The energy is 1/2 CV*V = 1/2 Q*Q/C (using Q = CV) Now just see what happens to the energy when you double V, double Q, etc. You need to think about what is constant each time. For example, for V is doubled but the capacitance should not change, so V*V ---%26gt; 2V*2V = 4 V*V and the energy will be four times as big. You also need to remember that capacitance is inversely proportional to separation, so if the separation is doubled, the capacitance is halved, etc.
